Differential Analytic Turing Automata
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Note 1
For the purposes of the NKS Forum my aim is to chart a course from general ideas about transformational equivalence classes of graphs to a notion of differential analytic turing automata (DATA). It may be a while before we get within sight of that goal, but it will provide some measure of motivation to name the thread after the envisioned end rather than the more homely starting place.
The basic idea here is that you have a species of graphs and a set of transformation rules that take you from one graph to another — and back again, as I'm only thinking of equational rules — and this partitions the species of graphs into transformational equivalence classes (TECs).
There are many interesting excursions to be had here, but I will focus mainly on logical applications, and and so the TECs I talk about will almost always have the character of logical equivalence classes (LECs).
An example that will figure heavily in the sequel is given by rooted trees as the species of graphs and a pair of equational transformation rules that derive from the graphical calculi of C.S. Peirce, as revived and extended by George Spencer Brown.
Here are the fundamental transformation rules, also referred to as the arithmetic axioms, more precisely, the arithmetic initials.
 |
(1) |
 |
(2) |
That should be enough to get started.
Note 2
I will be making use of the cactus language extension of Peirce's Alpha Graphs, so called because it uses a species of graphs that are usually called "cacti" in graph theory. The last exposition of the cactus syntax that I've written can be found here:
The representational and computational efficiency of the cactus language for the tasks that are usually associated with boolean algebra and propositional calculus makes it possible to entertain a further extension, to what we may call differential logic, because it develops this basic level of logic in the same way that differential calculus augments analytic geometry to handle change and diversity. There are several different introductions to differential logic that I have written and distributed across the Internet. You might start with the following couple of treatments:
I am currently rewriting these presentations in hopes of making them as clear as they can be, so please let me know if you have any questions.
Note 3
I will draw on those previously advertised resources of notation and theory as needed, but right now I sense the need for some concrete examples.
Let's say we have a system that is known by the name of its state space \(X\!\) and we have a boolean state variable \(x : X \to \mathbb{B},\) where \(\mathbb{B} = \{ 0, 1 \}.\)
We observe \(X\!\) for a while, relative to a discrete time frame, and we write down the following sequence of values for \(x.\!\)
|
\(\begin{array}{cc} t & x \\ 0 & 0 \\ 1 & 1 \\ 2 & 0 \\ 3 & 1 \\ 4 & 0 \\ 5 & 1 \\ 6 & 0 \\ 7 & 1 \\ 8 & 0 \\ 9 & \ldots \end{array}\) |
"Aha!" we say, and think we see the way of things, writing down the rule \(x' = (x),\!\) where \(x'\!\) is the state that comes next after \(x,\!\) and \((x)\!\) is the negation of \(x\!\) in boolean logic.
Another way to detect patterns is to write out a table of finite differences. For this example, we would get:
|
\(\begin{array}{ccccc} t & x & dx & d^2 x & \ldots \\ 0 & 0 & 1 & 0 & \ldots \\ 1 & 1 & 1 & 0 & \\ 2 & 0 & 1 & 0 & \\ 3 & 1 & 1 & 0 & \\ 4 & 0 & 1 & 0 & \\ 5 & 1 & 1 & 0 & \\ 6 & 0 & 1 & 0 & \\ 7 & 1 & 1 & 0 & \\ 8 & 0 & 1 & \ldots & \\ 9 & \ldots & \ldots & \ldots & \\ \end{array}\) |
And of course, all the higher order differences are zero.
This leads to thinking of \(X\!\) as having an extended state \((x, dx, d^2 x, \ldots, d^k x),\) and this additional language gives us the facility of describing state transitions in terms of the various orders of differences. For example, the rule \(x' = (x)\!\) can now be expressed by the rule \(dx = 1.\!\)
I'll leave you to muse on the possibilities of that.
Note 4
I am preparing a more fleshed-out 1-variable example, but in the mean time, for anybody who's finished all that other reading, there is a more detailed account of differential logic at the following thread heads: DLOG D. http://stderr.org/pipermail/inquiry/2003-May/thread.html#478 DLOG D. http://stderr.org/pipermail/inquiry/2003-June/thread.html#553 For future reference, here are a couple of handy rosetta stones for translating back and forth between different notations for the boolean functions f : B^k -> B, where k = 1, 2. DLOG D11. http://stderr.org/pipermail/inquiry/2003-May/000489.html
Note 5
For a slightly more interesting example, let's suppose that we have a dynamic system that is known by its state space X, and we have a boolean state variable x : X -> B. In addition, we are given an initial condition x = dx and a law d^2.x = (x). The initial condition has two cases: either x = dx = 0, or x = dx = 1. Here is a table of the two trajectories or "orbits" that we get by starting from each of the two permissible initial states and staying within the constraints of the dynamic law d^2.x = (x). d d d 0 1 2 x x x Initial State x dx 1 1 0 0 1 1 1 0 0 1 0 0 1 0 0 " " " Initial State (x)(dx) 0 0 1 0 1 1 1 0 0 1 0 0 1 0 0 " " " Note that the state x (dx) (d^2.x), that is, <x, dx, d^2.x> = <1, 0, 0>, is a stable attractor for both orbits. Further discussion of this example, complete with charts and graphs, can be found at this location: DLOG D20. http://stderr.org/pipermail/inquiry/2003-May/000498.html
Note 6
One more example may serve to suggest just how much dynamic
complexity can be built on a universe of discourse that has
but a single logical feature at its base.
But first, let me introduce a few more elements of general
notation that I'll be using to describe finite dimensional
universes of discourse and the qualitative dynamics that
we envision occurring in them.
Let !X! = {x_1, ..., x_n} be the "alphabet" of logical "features"
or "variables" that we use to describe the n-dimensional universe
of discourse X% = [!X!] = [x_1, ..., x_n]. Picturesquely viewed,
one may think of a venn diagram with n overlapping "circles" that
are labeled with the feature names in the set !X!. Staying with
this picture, one visualizes the universe of discourse X% = [!X!]
as having two layers: (1) the set X = <|!X!|> = <|x_1, ..., x_n|>
of "points" or "cells" -- in another sense of the word than when
we speak of "cellular automata" -- (2) the set X^ = (X -> B) of
"propositions", boolean-valued functions, or maps from X to B.
Thus, we may speak of the universe of discourse X% as being
an ordered pair <X, X^>, with 2^n points in the underlying
space X and 2^(2^n) propositions in the function space X^.
That's just life in Ascii-land. It ain't Chicago.
A more complete table setting out these notations can be found here:
DLOG D2. http://stderr.org/pipermail/inquiry/2003-May/000480.html
Now, to the Example.
Once again, let us begin with a 1-feature alphabet !X! = {x_1} = {x}.
In the discussion that follows I will consider a class of trajectories
that are ruled by the constraint that d^k.x = 0 for all k greater than
some fixed m, and I will indulge in the use of some picturesque speech
to describes salient classes of such curves. Given this finite order
condition, there is a highest order non-zero difference d^m.x that is
exhibited at each point in the course of any determinate trajectory.
Relative to any point of the corresponding orbit or curve, let us
call this highest order differential feature d^m.x the "drive"
at that point. Curves of constant drive d^m.x are then
referred to as "m^th gear curves".
One additional piece of notation will be needed here.
Starting from the base alphabet !X! = {x}, we define
and notate E^j.!X! = {x, d^1.x, d^2.x, ..., d^j.x}
as the "j^th order extended alphabet over !X!".
Let us now consider the family of 4^th gear curves through
the extended space E^4.X = <|x, dx, d^2.x, d^3.x, d^4.x|>.
These are the trajectories that are generated subject to
the law d^4.x = 1, where it is understood in making such
a statement that all higher order differences equal 0.
Since d^4.x and all higher order d^j.x are fixed, the entire dynamics
can be plotted in the extended space E^3.X = <|x, dx, d^2.x, d^3.x|>.
Thus, there is just enough room in a planar venn diagram to plot all
of these orbits and to show how they partition the points of E^3.X.
As it turns out, there are exactly two possible orbits, of eight
points each, as illustrated in Figures 16-a and 16-b. See here:
DLOG D23. http://stderr.org/pipermail/inquiry/2003-May/000502.html
Zoom^4 ...
Note 7
Here are the 4^th gear curves over the 1-feature universe X = <|x|> arranged in the form of tabular arrays, listing the extended state vectors <x, dx, d^2.x, d^3.x, d^4.x> as they occur in one cyclic period of each orbit. d d d d d 0 1 2 3 4 x x x x x Orbit 1 0 0 0 0 1 0 0 0 1 1 0 0 1 0 1 0 1 1 1 1 1 0 0 0 1 1 0 0 1 1 1 0 1 0 1 1 1 1 1 1 Orbit 2 1 1 0 0 1 0 1 0 1 1 1 1 1 0 1 0 0 1 1 1 0 1 0 0 1 1 1 0 1 1 0 1 1 0 1 1 0 1 1 1 In this arrangement, the temporal ordering of states can be reckoned by a kind of "parallel round-up rule". Specifically, if <a_k, a_[k+1]> is any pair of adjacent digits in a state vector <a_0, a_1, ..., a_n>, then the value of a_k in the next state is [a_k]' = a_k + a_[k+1], the addition being taken mod 2, of course. A more complete discussion of this arrangement is given here: DLOG D24. http://stderr.org/pipermail/inquiry/2003-May/000503.html
Note 8
I am going to tip-toe in silence/consilience past many questions of a philosophical nature/nurture that might be asked at this juncture, no doubt to revisit them at some future opportunity/importunity, however the cases happen to align in the course of their inevitable fall. Instead, let's "keep it concrete and simple", taking up the consideration of an incrementally more complex example, but having a slightly more general character than the orders of sequential transformations that we've been discussing up to this point. The types of logical transformations that I have in mind can be thought of as "transformations of discourse" because they map a universe of discourse into a universe of discourse by way of logical equations between the qualitative features or logical variables in the source and target universes. The sequential transformations or state transitions that we have been considering so far are actually special cases of these more general logical transformations, specifically, they are the ones that have a single universe of discourse, as it happens to exist at different moments in time, in the role of both the source and the target universes of the transformation in question. Onward and upward to Flatland, the differential analysis of transformations between 2-dimensional universes of discourse. Consider the transformation from the universe U% = [u, v] to the universe X% = [x, y] that is defined by this system of equations: x = f<u, v> = ((u)(v)) y = g<u, v> = ((u, v)) The parenthetical expressions on the right are the cactus forms for the boolean functions that correspond to inclusive disjunction and logical equivalence, respectively. By way of a reminder, consult Table 1 on the page at this location: DLOG D1. http://stderr.org/pipermail/inquiry/2003-May/000478.html The component notation F = <F_1, F_2> = <f, g> : U% -> X% allows us to give a name and a type to this transformation, and permits us to define it by means of the compact description that follows: <x, y> = F<u, v> = <((u)(v)), ((u, v))> The information that defines the logical transformation F can be represented in the form of a truth table, as below. u v | f g ----+---- 0 0 | 0 1 0 1 | 1 0 1 0 | 1 0 1 1 | 1 1 A more complete framework of discussion and a fuller development of this example can be found in the neighborhood of the following site: DLOG D73. http://stderr.org/pipermail/inquiry/2003-June/000557.html
Note 9
By virtue of Zipf's law -- yes, there is a dynamics to its economics -- I have found myself forced, when it comes to matters that I've been thinking about for "years and years" (YAY) to make a heavy, if not to say an overbearing use of acronyms, both for their utility as mnemonic devices and as a "regime of code compression" (ROCC). I'm well aware that this can be annoying at times, so please forgive what I hope will be a transient nuisance and I will do my level best to unpack these lexical quanta as we go. A "moral of the episode" (MOTE) on the wing here: A "transformation of textual elements" (TOTE) is a "formal or mathematical abstraction" (FOMA) of a very high order, to wit, a "formal object" (FO). As an object example, let us consider the TOTE in progress: <x, y> = F<u, v> = <((u)(v)), ((u, v))> Taken as a transformation from the universe U% = [u, v] to the universe X% = [x, y], this is a particular type of formal object, and it can be studied at that level of abstraction until the chickens come home to roost, as they say, but when the time comes to count those chickens, if you will, the terms of artifice that we use to talk about abstract objects, almost as if we actually knew what we were talking about, need to be fully fledged or fleshed out with extra "bits of interpretive data" (BOID's). And so, to decompress the story, the TOTE that we use to convey the FOMA has to be interpreted before it can be applied to anything that actually puts supper on the table, so to speak. What are some of the ways that an abstract logical transformation like F gets interpreted in the setting of a concrete application? Mathematical parlance comes part way to the rescue here and tosses us the line that a transformation of syntactic signs can be interpreted in either one of two ways, as an "alias" or as an "alibi". When we consider a transformation in the alias interpretation, we are merely changing the terms that we use to describe what may very well be, to some approximation, the very same things. For example, in some applications the discursive universes U% = [u, v] and X% = [x, y] are best understood as diverse frames, instruments, reticules, scopes, or templates, that we adopt for the sake of viewing from variant perspectives what we conceive to be roughly the same underlying objects. When we consider a transformation in the alibi interpretation, we are thinking of the objective things as objectively moving around in space or changing their qualitative characteristics. There are times when we think of this alibi transformation as taking place in a dimension of time, and then there are times when time is not an object. For example, in some applications the discursive universes U% = [u, v] and X% = [x, y] are actually the same universe, and what we have is a frame where x is the next state of u and y is the next state of v, notated as x = u' and y = v'. This permits us to rewrite the transformation F as follows: <u', v'> = F<u, v> = <((u)(v)), ((u, v))> All in all, then, we have three different ways in general of applying or interpreting a transformation of discourse, that we might sum up as one brand of alias and two brands of alibi, all together, the Elseword, Elsewhere, Elsewhen. No more angels on pinheads, the brass tacks next time.
Note 10
It is time to formulate the differential analysis of
a logical transformation, or a "mapping of discourse".
It is wise to begin with the first order differentials.
We are considering an abstract logical transformation
F = <f, g> : [u, v] -> [x, y] that can be interpreted
in a number of different ways. Let's fix on a couple
of major variants that might be indicated as follows:
Alias Map. <x , y > = F<u, v> = <((u)(v)), ((u, v))>
Alibi Map. <u', v'> = F<u, v> = <((u)(v)), ((u, v))>
F is just one example among -- well, now that I think of it --
how many other logical transformations from the same source
to the same target universe? In the light of that question,
maybe it would be advisable to contemplate the character of
F within the fold of its most closely akin transformations.
Given the alphabets !U! = {u, v} and !X! = {x, y},
along with the corresponding universes of discourse
U% and X% ~=~ [B^2], how many logical transformations
of the general form G = <G_1, G_2> : U% -> X% are there?
Since G_1 and G_2 can be any propositions of the type B^2 -> B,
there are 2^4 = 16 choices for each of the maps G_1 and G_2, and
thus there are 2^4 * 2^4 = 2^8 = 256 different mappings altogether
of the form G : U% -> X%. The set of all functions of a given type
is customarily denoted by placing its type indicator in parentheses,
in the present instance writing (U% -> X%) = {G : U% -> X%}, and so
the cardinality of this "function space" can be most conveniently
summed up by writing |(U% -> X%)| = |(B^2 -> B^2)| = 4^4 = 256.
Given any transformation of this type, G : U% -> X%, the (first order)
differential analysis of G is based on the definition of a couple of
further transformations, derived by way of operators on G, that ply
between the (first order) extended universes, EU% = [u, v, du, dv]
and EX% = [x, y, dx, dy], of G's own source and target universes.
First, the "enlargement map" (or the "secant transformation")
EG = <EG_1, EG_2> : EU% -> EX% is defined by the following
pair of component equations:
EG_1 = G_1 <u + du, v + dv>
EG_2 = G_2 <u + du, v + dv>
Second, the "difference map" (or the "chordal transformation")
DG = <DG_1, DG_2> : EU% -> EX% is defined in a component-wise
fashion as the boolean sum of the initial proposition G_j and
the enlarged or the "shifted" proposition EG_j, for j = 1, 2,
in accord with following pair of equations:
DG_1 = G_1 <u, v> + EG_1 <u, v, du, dv>
= G_1 <u, v> + G_1 <u + du, v + dv>
DG_2 = G_2 <u, v> + EG_2 <u, v, du, dv>
= G_2 <u, v> + G_2 <u + du, v + dv>
Maintaining a strict analogy with ordinary difference calculus
would perhaps have us write DG_j = EG_j - G_j, but the sum and
difference operations are the same thing in boolean arithmetic.
It is more often natural in the logical context to consider an
initial proposition q, then to compute the enlargement Eq, and
finally to determine the difference Dq = q + Eq, so we let the
variant order of terms reflect this sequence of considerations.
Given these general considerations about the operators E and D,
let's return to particular cases, and carry out the first order
analysis of the transformation F<u, v> = <((u)(v)), ((u, v))>.
Note 11
By way of getting our feet back on solid ground, let's crank up our current case of a transformation of discourse, F : U% -> X%, with concrete type [u, v] -> [x, y] or abstract type B^2 -> B^2, and let it spin through a sufficient number of turns to see how it goes, as viewed under the scope of what is probably its most straightforward view, as an elsewhen map F : [u, v] -> [u', v']. Elsewhen Map. <u', v'> = <((u)(v)), ((u, v))> u v Incipit 1. <u, v> = <0, 0> 0 0 0 1 1 0 1 0 " " Incipit 2. <u, v> = <1, 1> 1 1 1 1 " " In fine, there are two basins of attraction, the state <1, 0> and the state <1, 1>, with the orbit <0, 0>, <0, 1>, <1, 0> leading to the first basin and the orbit <1, 1> making up an isolated basin.
Note 12
Way back in DATA Note 3, we guessed, or "abduced", as a line of logicians from Aristotle to Peirce and beyond would say, the form of a rule that adequately accounts for the finite protocol of states that we observed the system X pass through, as spied in the light of its boolean state variable x : X -> B, and that rule is well-formulated in any of these styles of notation: 1.1. f : B -> B such that f : x ~> (x) 1.2. x' = (x) 1.3. x := (x) 1.4. dx = 1 In the current example, having read the manual first, I guess, we already know in advance the program that generates the state transitions, and it is a rule of the following equivalent and easily derivable forms: 2.1. F : B^2 -> B^2 such that F : <u, v> ~> <((u)(v)), ((u, v))> 2.2. u' = ((u)(v)), v' = ((u, v)) 2.3. u := ((u)(v)), v := ((u, v)) 2.4. ??? Well, the last one is not such a fall off the log, but that is exactly the purpose for which we have been developing all of the foregoing machinations. Here is what I got when I just went ahead and calculated the finite differences willy-nilly: Incipit 1. <u, v> = <0, 0> o-----o-----o-----o-----o-----o-----o | d d | d d | d d | d d | d d | ... | | 0 0 | 1 1 | 2 2 | 3 3 | 4 4 | ... | | u v | u v | u v | u v | u v | ... | o-----o-----o-----o-----o-----o-----o | 0 0 | 0 1 | 1 0 | 0 1 | 1 0 | ... | | 0 1 | 1 1 | 1 1 | 1 1 | 1 1 | ... | | 1 0 | 0 0 | 0 0 | 0 0 | 0 0 | ... | | 1 0 | 0 0 | 0 0 | 0 0 | 0 0 | ... | | " " | " " | " " | " " | " " | """ | o-----o-----o-----o-----o-----o-----o Incipit 2. <u, v> = <1, 1> o-----o-----o-----o-----o | d d | d d | d d | d d | | 0 0 | 1 1 | 2 2 | 3 3 | | u v | u v | u v | u v | o-----o-----o-----o-----o | 1 1 | 0 0 | 0 0 | = = | | 1 1 | 0 0 | 0 0 | = = | | " " | " " | " " | " " | o-----o-----o-----o-----o To be honest, I have never thought of trying to hack the problem in such a brute-force way until just now, and so I know enough to expect a not unappreciable probability of error about all that I've taken the risk to write out here, but let me forge ahead and see what I can see. What we are looking for is -- one rule to rule them all, a rule that applies to every state and works every time. What we see at first sight in the tables above are patterns of differential features that attach to the states in each orbit of the dynamics. Looked at locally to these orbits, the isolated fixed point at <1, 1> is no problem, as the rule du = dv = 0 describes it pithily enough. When it comes to the other orbit, the first thing that comes to mind is to write out the law du = v, dv = (u). I am going to take a nap to clear my head.
Note 13
I think that it ought to be clear at this point that we need a more systematic symbolic method for computing the differentials of logical transformations, using the term "differential" in a loose way at present for all sorts of finite differences and derivatives, leaving it to another discussion to sharpen up its more exact technical senses. For convenience of reference, let's recast our current example in the form F = <f, g> = <((u)(v)), ((u, v))>. In their application to this logical transformation the operators E and D respectively produce the "enlarged map" EF = <Ef, Eg> and the "difference map" DF = <Df, Dg>, whose components can be given as follows, if the reader, in the absence of a special format for logical parentheses, can forgive syntactically 2-lingual phrases: Ef = ((u + du)(v + dv)) Eg = ((u + du, v + dv)) Df = ((u)(v)) + ((u + du)(v + dv)) Dg = ((u, v)) + ((u + du, v + dv)) But these initial formulas are purely definitional, and help us little to understand either the purpose of the operators or the significance of the results. Working symbolically, let's apply a more systematic method to the separate components of the mapping F. A sketch of this work is presented in the following series of Figures, where each logical proposition is expanded over the basic cells uv, u(v), (u)v, (u)(v) of the 2-dimensional universe of discourse U% = [u, v]. Computation Summary for f<u, v> = ((u)(v)) Figure 1.1 expands f = ((u)(v)) over [u, v] to produce the equivalent exclusive disjunction uv + u(v) + (u)v. o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/%\%%%%%/%\``````````````| |`````````````/%%%\%%%/%%%\`````````````| |````````````/%%%%%\%/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/%\%%%%%/%\``````````| |`````````/%%%\%%%/%%%\%%%/%%%\`````````| |````````/%%%%%\%/%%%%%\%/%%%%%\````````| |```````o%%%%%%%o%%%%%%%o%%%%%%%o```````| |``````/%\%%%%%/%\%%%%%/%\%%%%%/%\``````| |`````/%%%\%%%/%%%\%%%/%%%\%%%/%%%\`````| |````/%%%%%\%/%%%%%\%/%%%%%\%/%%%%%\````| |```o%%%%%%%o%%%%%%%o%%%%%%%o%%%%%%%o```| |```|\%%%%%/%\%%%%%/`\%%%%%/%\%%%%%/|```| |```|`\%%%/%%%\%%%/```\%%%/%%%\%%%/`|```| |```|``\%/%%%%%\%/`````\%/%%%%%\%/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/`\`````/`\%%%%%/|```|```| |```|```|`\%%%/```\```/```\%%%/`|```|```| |```|`u`|``\%/`````\`/`````\%/``|`v`|```| |```o---+---o```````o```````o---+---o```| |```````|````\`````/`\`````/````|```````| |```````|`````\```/```\```/`````|```````| |```````|`du```\`/`````\`/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.1. f = ((u)(v)) Figure 1.2 expands Ef = ((u + du)(v + dv)) over [u, v] to give: uv.(du dv) + u(v).(du (dv)) + (u)v.((du) dv) + (u)(v).((du)(dv)) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/%\%%%%%/%\``````````````| |`````````````/%%%\%%%/%%%\`````````````| |````````````/%%%%%\%/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/`\%%%%%/%\``````````| |`````````/%%%\%%%/```\%%%/%%%\`````````| |````````/%%%%%\%/`````\%/%%%%%\````````| |```````o%%%%%%%o```````o%%%%%%%o```````| |``````/%\%%%%%/%\`````/%\%%%%%/%\``````| |`````/%%%\%%%/%%%\```/%%%\%%%/%%%\`````| |````/%%%%%\%/%%%%%\`/%%%%%\%/%%%%%\````| |```o%%%%%%%o%%%%%%%o%%%%%%%o%%%%%%%o```| |```|\%%%%%/`\%%%%%/%\%%%%%/`\%%%%%/|```| |```|`\%%%/```\%%%/%%%\%%%/```\%%%/`|```| |```|``\%/`````\%/%%%%%\%/`````\%/``|```| |```|```o```````o%%%%%%%o```````o```|```| |```|```|\`````/%\%%%%%/%\`````/|```|```| |```|```|`\```/%%%\%%%/%%%\```/`|```|```| |```|`u`|``\`/%%%%%\%/%%%%%\`/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.2. Ef = ((u + du)(v + dv)) Figure 1.3 expands Df = f + Ef over [u, v] to produce: uv.du dv + u(v).du(dv) + (u)v.(du)dv + (u)(v).((du)(dv)) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/`\`````/`\``````````````| |`````````````/```\```/```\`````````````| |````````````/`````\`/`````\````````````| |```````````o```````o```````o```````````| |``````````/`\`````/%\`````/`\``````````| |`````````/```\```/%%%\```/```\`````````| |````````/`````\`/%%%%%\`/`````\````````| |```````o```````o%%%%%%%o```````o```````| |``````/`\`````/`\%%%%%/`\`````/`\``````| |`````/```\```/```\%%%/```\```/```\`````| |````/`````\`/`````\%/`````\`/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/%\`````/%\`````/|```| |```|`\```/%%%\```/%%%\```/%%%\```/`|```| |```|``\`/%%%%%\`/%%%%%\`/%%%%%\`/``|```| |```|```o%%%%%%%o%%%%%%%o%%%%%%%o```|```| |```|```|\%%%%%/%\%%%%%/%\%%%%%/|```|```| |```|```|`\%%%/%%%\%%%/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\%/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.3. Df = f + Ef I'll break this here in case anyone wants to try and do the work for g on their own.
Note 14
No doubt everybody who's still awake sacrificed the few spare moments of their sleep last night that it took to Figure all this out already, but just for the record here's what I got: Computation Summary for g<u, v> = ((u, v)) Figure 2.1 expands g = ((u, v)) over [u, v] into the equivalent exclusive disjunction uv + (u)(v). o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/%\%%%%%/%\``````````````| |`````````````/%%%\%%%/%%%\`````````````| |````````````/%%%%%\%/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/`\%%%%%/%\%%%%%/`\``````````| |`````````/```\%%%/%%%\%%%/```\`````````| |````````/`````\%/%%%%%\%/`````\````````| |```````o```````o%%%%%%%o```````o```````| |``````/`\`````/`\%%%%%/`\`````/`\``````| |`````/```\```/```\%%%/```\```/```\`````| |````/`````\`/`````\%/`````\`/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/`\`````/%\`````/`\`````/|```| |```|`\```/```\```/%%%\```/```\```/`|```| |```|``\`/`````\`/%%%%%\`/`````\`/``|```| |```|```o```````o%%%%%%%o```````o```|```| |```|```|\`````/%\%%%%%/%\`````/|```|```| |```|```|`\```/%%%\%%%/%%%\```/`|```|```| |```|`u`|``\`/%%%%%\%/%%%%%\`/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/%\%%%%%/````|```````| |```````|`````\%%%/%%%\%%%/`````|```````| |```````|`du```\%/%%%%%\%/```dv`|```````| |```````o-------o%%%%%%%o-------o```````| |````````````````\%%%%%/````````````````| |`````````````````\%%%/`````````````````| |``````````````````\%/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.1. g = ((u, v)) Figure 2.2 expands Eg = ((u + du, v + dv)) over [u, v] to give: uv.((du, dv)) + u(v).(du, dv) + (u)v.(du, dv) + (u)(v).((du, dv)) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/`\%%%%%/`\``````````````| |`````````````/```\%%%/```\`````````````| |````````````/`````\%/`````\````````````| |```````````o```````o```````o```````````| |``````````/%\`````/%\`````/%\``````````| |`````````/%%%\```/%%%\```/%%%\`````````| |````````/%%%%%\`/%%%%%\`/%%%%%\````````| |```````o%%%%%%%o%%%%%%%o%%%%%%%o```````| |``````/`\%%%%%/`\%%%%%/`\%%%%%/`\``````| |`````/```\%%%/```\%%%/```\%%%/```\`````| |````/`````\%/`````\%/`````\%/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/%\`````/%\`````/|```| |```|`\```/%%%\```/%%%\```/%%%\```/`|```| |```|``\`/%%%%%\`/%%%%%\`/%%%%%\`/``|```| |```|```o%%%%%%%o%%%%%%%o%%%%%%%o```|```| |```|```|\%%%%%/`\%%%%%/`\%%%%%/|```|```| |```|```|`\%%%/```\%%%/```\%%%/`|```|```| |```|`u`|``\%/`````\%/`````\%/``|`v`|```| |```o---+---o```````o```````o---+---o```| |```````|````\`````/%\`````/````|```````| |```````|`````\```/%%%\```/`````|```````| |```````|`du```\`/%%%%%\`/```dv`|```````| |```````o-------o%%%%%%%o-------o```````| |````````````````\%%%%%/````````````````| |`````````````````\%%%/`````````````````| |``````````````````\%/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.2. Eg = ((u + du, v + dv)) Figure 2.3 expands Dg = g + Eg over [u, v] to yield the form: uv.(du, dv) + u(v).(du, dv) + (u)v.(du, dv) + (u)(v).(du, dv) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/%\`````/%\``````````````| |`````````````/%%%\```/%%%\`````````````| |````````````/%%%%%\`/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/`\%%%%%/%\``````````| |`````````/%%%\%%%/```\%%%/%%%\`````````| |````````/%%%%%\%/`````\%/%%%%%\````````| |```````o%%%%%%%o```````o%%%%%%%o```````| |``````/`\%%%%%/`\`````/`\%%%%%/`\``````| |`````/```\%%%/```\```/```\%%%/```\`````| |````/`````\%/`````\`/`````\%/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/`\`````/%\`````/|```| |```|`\```/%%%\```/```\```/%%%\```/`|```| |```|``\`/%%%%%\`/`````\`/%%%%%\`/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/%\`````/%\%%%%%/|```|```| |```|```|`\%%%/%%%\```/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\`/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.3. Dg = g + Eg
Note 15
| 'Tis a derivative from me to mine, | And only that I stand for. | | Winter's Tale, 3.2.43-44 We've talked about differentials long enough that I think it's past time we met with some. When the term is being used with its more exact sense, a "differential" is a locally linear approximation to a function, in the context of this logical discussion, then, a locally linear approximation to a proposition. I think that it would be best to just go ahead and exhibit the simplest form of a differential dF for the current example of a logical transformation F, after which the majority of the easiest questions will've been answered in visually intuitive terms. For F = <f, g> we have dF = <df, dg>, and so we can proceed componentwise, patching the pieces back together at the end. We have prepared the ground already by computing these terms: Ef = ((u + du)(v + dv)) Eg = ((u + du, v + dv)) Df = ((u)(v)) + ((u + du)(v + dv)) Dg = ((u, v)) + ((u + du, v + dv)) As a matter of fact, computing the symmetric differences Df = f + Ef and Dg = g + Eg has already taken care of the "localizing" part of the task by subtracting out the forms of f and g from the forms of Ef and Eg, respectively. Thus all we have left to do is to decide what linear propositions best approximate the difference maps Df and Dg, respectively. This raises the question: What is a linear proposition? The answer that makes the most sense in this context is this: A proposition is just a boolean-valued function, so a linear proposition is a linear function into the boolean space B. In particular, the linear functions that we want will be linear functions in the differential variables du and dv. As it turns out, there are just four linear propositions in the associated "differential universe" dU% = [du, dv], and these are the propositions that are commonly denoted: 0, du, dv, du + dv, in other words, (), du, dv, (du, dv).
Note 16
| for equalities are so weighed | that curiosity in neither can | make choice of either's moiety. | | King Lear, Sc.1.5-7, (Quarto) | for qualities are so weighed | that curiosity in neither can | make choice of either's moiety. | | King Lear, 1.1.5-6, (Folio) Justifying a notion of approximation is a little more involved in general, and especially in these discrete logical spaces, than it would be expedient for people in a hurry to tangle with right now. I will just say that there are "naive" or "obvious" notions and there are "sophisticated" or "subtle" notions that we might choose among. The later would engage us in trying to construct proper logical analogues of Lie derivatives, and so let's save that for when we have become subtle or sophisticated or both. Against or toward that day, as you wish, let's begin with an option in plain view. Figure 1.4 illustrates one way of ranging over the cells of the underlying universe U% = [u, v] and selecting at each cell the linear proposition in dU% = [du, dv] that best approximates the patch of the difference map Df that is located there, yielding the following formula for the differential df. df = uv.0 + u(v).du + (u)v.dv + (u)(v).(du, dv) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/`\`````/`\``````````````| |`````````````/```\```/```\`````````````| |````````````/`````\`/`````\````````````| |```````````o```````o```````o```````````| |``````````/`\`````/`\`````/`\``````````| |`````````/```\```/```\```/```\`````````| |````````/`````\`/`````\`/`````\````````| |```````o```````o```````o```````o```````| |``````/`\`````/%\`````/%\`````/`\``````| |`````/```\```/%%%\```/%%%\```/```\`````| |````/`````\`/%%%%%\`/%%%%%\`/`````\````| |```o```````o%%%%%%%o%%%%%%%o```````o```| |```|\`````/%\%%%%%/`\%%%%%/%\`````/|```| |```|`\```/%%%\%%%/```\%%%/%%%\```/`|```| |```|``\`/%%%%%\%/`````\%/%%%%%\`/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/%\`````/%\%%%%%/|```|```| |```|```|`\%%%/%%%\```/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\`/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.4. df = linear approx to Df Figure 2.4. illustrates one way of ranging over the cells of the underlying universe U% = [u, v] and selecting at each cell the linear proposition in dU% = [du, dv] that best approximates the patch of the difference map Dg that is located there, yielding the following formula for the differential dg. dg = uv.(du, dv) + u(v).(du, dv) + (u)v.(du, dv) + (u)(v).(du, dv) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/%\`````/%\``````````````| |`````````````/%%%\```/%%%\`````````````| |````````````/%%%%%\`/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/`\%%%%%/%\``````````| |`````````/%%%\%%%/```\%%%/%%%\`````````| |````````/%%%%%\%/`````\%/%%%%%\````````| |```````o%%%%%%%o```````o%%%%%%%o```````| |``````/`\%%%%%/`\`````/`\%%%%%/`\``````| |`````/```\%%%/```\```/```\%%%/```\`````| |````/`````\%/`````\`/`````\%/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/`\`````/%\`````/|```| |```|`\```/%%%\```/```\```/%%%\```/`|```| |```|``\`/%%%%%\`/`````\`/%%%%%\`/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/%\`````/%\%%%%%/|```|```| |```|```|`\%%%/%%%\```/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\`/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.4. dg = linear approx to Dg Well, g, that was easy, seeing as how Dg is already linear at each locus, dg = Dg.
Note 17
We have been conducting the differential analysis of the logical transformation F : [u, v] -> [u, v] defined as F : <u, v> ~> <((u)(v)), ((u, v))>, and this means starting with the extended transformation EF : [u, v, du, dv] -> [u, v, du, dv] and breaking it into an analytic series, EF = F + dF + d^2.F + ..., and so on until there is nothing left to analyze any further. As a general rule, one proceeds by way of the following stages: 1. EF = [d^0]F + [r^0]F 2. [r^0]F = [d^1]F + [r^1]F 3. [r^1]F = [d^2]F + [r^2]F 4. ... In our analysis of the current transformation F, we carried out Step 1 in the more familiar form EF = F + DF, and we have just reached Step 2 in the form DF = dF + rF, where rF is the residual term that remains for us to examine next. NB. I'm am trying to give quick overview here, and this forces me to omit many picky details. The picky reader may wish to consult the more detailed presentation of this material in the following ur-neighborhoods: Jon Awbrey, "Differential Logic and Dynamic Systems" DLOG D. http://stderr.org/pipermail/inquiry/2003-May/thread.html#478 DLOG D. http://stderr.org/pipermail/inquiry/2003-June/thread.html#553 Especially: DLOG D40. http://stderr.org/pipermail/inquiry/2003-May/000521.html DLOG D71. http://stderr.org/pipermail/inquiry/2003-June/000554.html Take your pick, Gimli ...
Note 18
Let's push on with the analysis of the transformation: F : <u, v> ~> <f<u, v>, g<u, v>> = <((u)(v)), ((u, v))> For ease of comparison and computation, I will collect the Figures that we need for the remainder of the work together on one page. Computation Summary for f<u, v> = ((u)(v)) Figure 1.1 expands f = ((u)(v)) over [u, v] to produce the equivalent exclusive disjunction uv + u(v) + (u)v. Figure 1.2 expands Ef = ((u + du)(v + dv)) over [u, v] to arrive at Ef = uv (du dv) + u(v) (du (dv)) + (u)v ((du) dv) + (u)(v)((du)(dv)). Ef tells you what you would have to do, from where you are in the universe [u, v], if you want to end up in a place where f is true. In this case, where the prevailing proposition f is ((u)(v)), the indication uv (du dv) of Ef tells you this: If u and v are both true where you are, then just don't change both u and v at once, and you will end up in a place where ((u)(v)) is true. Figure 1.3 expands Df over [u, v] to end up with the formula: Df = uv du dv + u(v) du(dv) + (u)v (du)dv + (u)(v)((du)(dv)). Df tells you what you would have to do, from where you are in the universe [u, v], if you want to bring about a change in the value of f, that is, if you want to get to a place where the value of f is different from what it is where you are. In the present case, where the reigning proposition f is ((u)(v)), the term uv du dv of Df tells you this: If u and v are both true where you are, then you would have to change both u and v in order to reach a place where the value of f is different from what it is where you are. Figure 1.4 approximates Df by the linear form df = uv 0 + u(v) du + (u)v dv + (u)(v)(du, dv). Figure 1.5 shows what remains of the difference map Df when the first order linear contribution df is removed: rf = uv du dv + u(v) du dv + (u)v du dv + (u)(v) du dv. This form can be written more succinctly as rf = du dv. o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/%\%%%%%/%\``````````````| |`````````````/%%%\%%%/%%%\`````````````| |````````````/%%%%%\%/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/%\%%%%%/%\``````````| |`````````/%%%\%%%/%%%\%%%/%%%\`````````| |````````/%%%%%\%/%%%%%\%/%%%%%\````````| |```````o%%%%%%%o%%%%%%%o%%%%%%%o```````| |``````/%\%%%%%/%\%%%%%/%\%%%%%/%\``````| |`````/%%%\%%%/%%%\%%%/%%%\%%%/%%%\`````| |````/%%%%%\%/%%%%%\%/%%%%%\%/%%%%%\````| |```o%%%%%%%o%%%%%%%o%%%%%%%o%%%%%%%o```| |```|\%%%%%/%\%%%%%/`\%%%%%/%\%%%%%/|```| |```|`\%%%/%%%\%%%/```\%%%/%%%\%%%/`|```| |```|``\%/%%%%%\%/`````\%/%%%%%\%/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/`\`````/`\%%%%%/|```|```| |```|```|`\%%%/```\```/```\%%%/`|```|```| |```|`u`|``\%/`````\`/`````\%/``|`v`|```| |```o---+---o```````o```````o---+---o```| |```````|````\`````/`\`````/````|```````| |```````|`````\```/```\```/`````|```````| |```````|`du```\`/`````\`/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.1. f = ((u)(v)) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/%\%%%%%/%\``````````````| |`````````````/%%%\%%%/%%%\`````````````| |````````````/%%%%%\%/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/`\%%%%%/%\``````````| |`````````/%%%\%%%/```\%%%/%%%\`````````| |````````/%%%%%\%/`````\%/%%%%%\````````| |```````o%%%%%%%o```````o%%%%%%%o```````| |``````/%\%%%%%/%\`````/%\%%%%%/%\``````| |`````/%%%\%%%/%%%\```/%%%\%%%/%%%\`````| |````/%%%%%\%/%%%%%\`/%%%%%\%/%%%%%\````| |```o%%%%%%%o%%%%%%%o%%%%%%%o%%%%%%%o```| |```|\%%%%%/`\%%%%%/%\%%%%%/`\%%%%%/|```| |```|`\%%%/```\%%%/%%%\%%%/```\%%%/`|```| |```|``\%/`````\%/%%%%%\%/`````\%/``|```| |```|```o```````o%%%%%%%o```````o```|```| |```|```|\`````/%\%%%%%/%\`````/|```|```| |```|```|`\```/%%%\%%%/%%%\```/`|```|```| |```|`u`|``\`/%%%%%\%/%%%%%\`/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.2. Ef = ((u + du)(v + dv)) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/`\`````/`\``````````````| |`````````````/```\```/```\`````````````| |````````````/`````\`/`````\````````````| |```````````o```````o```````o```````````| |``````````/`\`````/%\`````/`\``````````| |`````````/```\```/%%%\```/```\`````````| |````````/`````\`/%%%%%\`/`````\````````| |```````o```````o%%%%%%%o```````o```````| |``````/`\`````/`\%%%%%/`\`````/`\``````| |`````/```\```/```\%%%/```\```/```\`````| |````/`````\`/`````\%/`````\`/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/%\`````/%\`````/|```| |```|`\```/%%%\```/%%%\```/%%%\```/`|```| |```|``\`/%%%%%\`/%%%%%\`/%%%%%\`/``|```| |```|```o%%%%%%%o%%%%%%%o%%%%%%%o```|```| |```|```|\%%%%%/%\%%%%%/%\%%%%%/|```|```| |```|```|`\%%%/%%%\%%%/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\%/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.3. Difference Map Df = f + Ef o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/`\`````/`\``````````````| |`````````````/```\```/```\`````````````| |````````````/`````\`/`````\````````````| |```````````o```````o```````o```````````| |``````````/`\`````/`\`````/`\``````````| |`````````/```\```/```\```/```\`````````| |````````/`````\`/`````\`/`````\````````| |```````o```````o```````o```````o```````| |``````/`\`````/%\`````/%\`````/`\``````| |`````/```\```/%%%\```/%%%\```/```\`````| |````/`````\`/%%%%%\`/%%%%%\`/`````\````| |```o```````o%%%%%%%o%%%%%%%o```````o```| |```|\`````/%\%%%%%/`\%%%%%/%\`````/|```| |```|`\```/%%%\%%%/```\%%%/%%%\```/`|```| |```|``\`/%%%%%\%/`````\%/%%%%%\`/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/%\`````/%\%%%%%/|```|```| |```|```|`\%%%/%%%\```/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\`/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.4. Linear Proxy df for Df o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/`\`````/`\``````````````| |`````````````/```\```/```\`````````````| |````````````/`````\`/`````\````````````| |```````````o```````o```````o```````````| |``````````/`\`````/%\`````/`\``````````| |`````````/```\```/%%%\```/```\`````````| |````````/`````\`/%%%%%\`/`````\````````| |```````o```````o%%%%%%%o```````o```````| |``````/`\`````/%\%%%%%/%\`````/`\``````| |`````/```\```/%%%\%%%/%%%\```/```\`````| |````/`````\`/%%%%%\%/%%%%%\`/`````\````| |```o```````o%%%%%%%o%%%%%%%o```````o```| |```|\`````/`\%%%%%/%\%%%%%/`\`````/|```| |```|`\```/```\%%%/%%%\%%%/```\```/`|```| |```|``\`/`````\%/%%%%%\%/`````\`/``|```| |```|```o```````o%%%%%%%o```````o```|```| |```|```|\`````/`\%%%%%/`\`````/|```|```| |```|```|`\```/```\%%%/```\```/`|```|```| |```|`u`|``\`/`````\%/`````\`/``|`v`|```| |```o---+---o```````o```````o---+---o```| |```````|````\`````/`\`````/````|```````| |```````|`````\```/```\```/`````|```````| |```````|`du```\`/`````\`/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 1.5. Remainder rf = Df + df Computation Summary for g<u, v> = ((u, v)) Exercise for the Reader.
Note 19
I'd never rob readers of exercise ... but for my ain sense of an ending --- Computation Summary for g<u, v> = ((u, v)) Figure 2.1 expands g = ((u, v)) over [u, v] to get the equivalent exclusive disjunction u v + (u)(v). Figure 2.2 expands Eg = ((u + du, v + dv)) over [u, v] to arrive at Eg = uv((du, dv)) + u(v)(du, dv) + (u)v (du, dv) + (u)(v)((du, dv)). Eg tells you what you would have to do, from where you are in the universe [u, v], if you want to end up in a place where g is true. In this case, where the prevailing proposition g is ((u, v)), the component uv((du, dv)) of Eg tells you this: If u and v are both true where you are, then change either both or neither u and v at the same time, and you will attain a place where ((u, v)) is true. Figure 2.3 expands Dg over [u, v] to obtain the following formula: Dg = uv (du, dv) + u(v)(du, dv) + (u)v (du, dv) + (u)(v) (du, dv). Dg tells you what you would have to do, from where you are in the universe [u, v], if you want to bring about a change in the value of g, that is, if you want to get to a place where the value of g is different from what it is where you are. In the present case, where the ruling proposition g is ((u, v)), the term uv (du, dv) of Dg tells you this: If u and v are both true where you are, then you would have to change one or the other but not both u and v in order to reach a place where the value of g is different from what it is where you are. Figure 2.4 approximates Dg in the proxy of the linear proposition dg = uv (du, dv) + u(v)(du, dv) + (u)v (du, dv) + (u)(v) (du, dv). Noting the caste of the constant factor (du, dv) distributed over the expansion of a tautology, dg may be digested as dg = (du, dv). Figure 2.5 shows what remains of the difference map Dg when the first order linear contribution dg is removed, and this is nothing but nothing at all, leaving rg = 0. o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/%\%%%%%/%\``````````````| |`````````````/%%%\%%%/%%%\`````````````| |````````````/%%%%%\%/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/`\%%%%%/%\%%%%%/`\``````````| |`````````/```\%%%/%%%\%%%/```\`````````| |````````/`````\%/%%%%%\%/`````\````````| |```````o```````o%%%%%%%o```````o```````| |``````/`\`````/`\%%%%%/`\`````/`\``````| |`````/```\```/```\%%%/```\```/```\`````| |````/`````\`/`````\%/`````\`/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/`\`````/%\`````/`\`````/|```| |```|`\```/```\```/%%%\```/```\```/`|```| |```|``\`/`````\`/%%%%%\`/`````\`/``|```| |```|```o```````o%%%%%%%o```````o```|```| |```|```|\`````/%\%%%%%/%\`````/|```|```| |```|```|`\```/%%%\%%%/%%%\```/`|```|```| |```|`u`|``\`/%%%%%\%/%%%%%\`/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/%\%%%%%/````|```````| |```````|`````\%%%/%%%\%%%/`````|```````| |```````|`du```\%/%%%%%\%/```dv`|```````| |```````o-------o%%%%%%%o-------o```````| |````````````````\%%%%%/````````````````| |`````````````````\%%%/`````````````````| |``````````````````\%/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.1. g = ((u, v)) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/%\``````````````````| |`````````````````/%%%\`````````````````| |````````````````/%%%%%\````````````````| |```````````````o%%%%%%%o```````````````| |``````````````/`\%%%%%/`\``````````````| |`````````````/```\%%%/```\`````````````| |````````````/`````\%/`````\````````````| |```````````o```````o```````o```````````| |``````````/%\`````/%\`````/%\``````````| |`````````/%%%\```/%%%\```/%%%\`````````| |````````/%%%%%\`/%%%%%\`/%%%%%\````````| |```````o%%%%%%%o%%%%%%%o%%%%%%%o```````| |``````/`\%%%%%/`\%%%%%/`\%%%%%/`\``````| |`````/```\%%%/```\%%%/```\%%%/```\`````| |````/`````\%/`````\%/`````\%/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/%\`````/%\`````/|```| |```|`\```/%%%\```/%%%\```/%%%\```/`|```| |```|``\`/%%%%%\`/%%%%%\`/%%%%%\`/``|```| |```|```o%%%%%%%o%%%%%%%o%%%%%%%o```|```| |```|```|\%%%%%/`\%%%%%/`\%%%%%/|```|```| |```|```|`\%%%/```\%%%/```\%%%/`|```|```| |```|`u`|``\%/`````\%/`````\%/``|`v`|```| |```o---+---o```````o```````o---+---o```| |```````|````\`````/%\`````/````|```````| |```````|`````\```/%%%\```/`````|```````| |```````|`du```\`/%%%%%\`/```dv`|```````| |```````o-------o%%%%%%%o-------o```````| |````````````````\%%%%%/````````````````| |`````````````````\%%%/`````````````````| |``````````````````\%/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.2. Eg = ((u + du, v + dv)) o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/%\`````/%\``````````````| |`````````````/%%%\```/%%%\`````````````| |````````````/%%%%%\`/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/`\%%%%%/%\``````````| |`````````/%%%\%%%/```\%%%/%%%\`````````| |````````/%%%%%\%/`````\%/%%%%%\````````| |```````o%%%%%%%o```````o%%%%%%%o```````| |``````/`\%%%%%/`\`````/`\%%%%%/`\``````| |`````/```\%%%/```\```/```\%%%/```\`````| |````/`````\%/`````\`/`````\%/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/`\`````/%\`````/|```| |```|`\```/%%%\```/```\```/%%%\```/`|```| |```|``\`/%%%%%\`/`````\`/%%%%%\`/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/%\`````/%\%%%%%/|```|```| |```|```|`\%%%/%%%\```/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\`/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.3. Difference Map Dg = g + Eg o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/%\`````/%\``````````````| |`````````````/%%%\```/%%%\`````````````| |````````````/%%%%%\`/%%%%%\````````````| |```````````o%%%%%%%o%%%%%%%o```````````| |``````````/%\%%%%%/`\%%%%%/%\``````````| |`````````/%%%\%%%/```\%%%/%%%\`````````| |````````/%%%%%\%/`````\%/%%%%%\````````| |```````o%%%%%%%o```````o%%%%%%%o```````| |``````/`\%%%%%/`\`````/`\%%%%%/`\``````| |`````/```\%%%/```\```/```\%%%/```\`````| |````/`````\%/`````\`/`````\%/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/%\`````/`\`````/%\`````/|```| |```|`\```/%%%\```/```\```/%%%\```/`|```| |```|``\`/%%%%%\`/`````\`/%%%%%\`/``|```| |```|```o%%%%%%%o```````o%%%%%%%o```|```| |```|```|\%%%%%/%\`````/%\%%%%%/|```|```| |```|```|`\%%%/%%%\```/%%%\%%%/`|```|```| |```|`u`|``\%/%%%%%\`/%%%%%\%/``|`v`|```| |```o---+---o%%%%%%%o%%%%%%%o---+---o```| |```````|````\%%%%%/`\%%%%%/````|```````| |```````|`````\%%%/```\%%%/`````|```````| |```````|`du```\%/`````\%/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.4. Linear Proxy dg for Dg o---------------------------------------o |```````````````````````````````````````| |```````````````````o```````````````````| |``````````````````/`\``````````````````| |`````````````````/```\`````````````````| |````````````````/`````\````````````````| |```````````````o```````o```````````````| |``````````````/`\`````/`\``````````````| |`````````````/```\```/```\`````````````| |````````````/`````\`/`````\````````````| |```````````o```````o```````o```````````| |``````````/`\`````/`\`````/`\``````````| |`````````/```\```/```\```/```\`````````| |````````/`````\`/`````\`/`````\````````| |```````o```````o```````o```````o```````| |``````/`\`````/`\`````/`\`````/`\``````| |`````/```\```/```\```/```\```/```\`````| |````/`````\`/`````\`/`````\`/`````\````| |```o```````o```````o```````o```````o```| |```|\`````/`\`````/`\`````/`\`````/|```| |```|`\```/```\```/```\```/```\```/`|```| |```|``\`/`````\`/`````\`/`````\`/``|```| |```|```o```````o```````o```````o```|```| |```|```|\`````/`\`````/`\`````/|```|```| |```|```|`\```/```\```/```\```/`|```|```| |```|`u`|``\`/`````\`/`````\`/``|`v`|```| |```o---+---o```````o```````o---+---o```| |```````|````\`````/`\`````/````|```````| |```````|`````\```/```\```/`````|```````| |```````|`du```\`/`````\`/```dv`|```````| |```````o-------o```````o-------o```````| |````````````````\`````/````````````````| |`````````````````\```/`````````````````| |``````````````````\`/``````````````````| |```````````````````o```````````````````| |```````````````````````````````````````| o---------------------------------------o Figure 2.5. Remainder rg = Dg + dg | Have I carved enough, my lord -- | Child, you are a bone. | | Leonard Cohen, "Teachers" (1967)
Note 20
In my work on "Differential Logic and Dynamic Systems", I found it useful to develop several different ways of visualizing logical transformations, indeed, I devised four distinct styles of picture for the job. Thus far in our work on the mapping F : [u, v] -> [u, v], we've been making use of what I call the "areal view" of the extended universe of discourse, [u, v, du, dv], but as the number of dimensions climbs beyond four, it's time to bid this genre adieu, and look for a style that can scale a little better. At any rate, before we proceed any further, let's first assemble the information that we have gathered about F from several different angles, and see if it can be fitted into a coherent picture of the transformation F : <u, v> ~> <((u)(v)), ((u, v))>. In our first crack at the transformation F, we simply plotted the state transitions and applied the utterly stock technique of calculating the finite differences. Orbit 1. u v o-----o-----o | ` ` | d d | | u v | u v | o=====o=====o | 1 1 | 0 0 | | " " | " " | o-----o-----o A quick inspection of the first Table suggests a rule to cover the case when u = v = 1, namely, du = dv = 0. To put it another way, the Table characterizes Orbit 1 by means of the data: <u, v, du, dv> = <1, 1, 0, 0>. Last but not least, yet another way to convey the same information is by means of the (first order) extended proposition: u v (du)(dv). Orbit 2. (u v) o-----o-----o-----o | ` ` | ` ` | d d | | ` ` | d d | 2 2 | | u v | u v | u v | o=====o=====o=====o | 0 0 | 0 1 | 1 0 | | 0 1 | 1 1 | 1 1 | | 1 0 | 0 0 | 0 0 | | " " | " " | " " | o-----o-----o-----o A more fine combing of the second Table brings to mind a rule that partly covers the remaining cases, that is, du = v, dv = (u). To vary the formulation, this Table characterizes Orbit 2 by means of the following vector equation: <du, dv> = <v, (u)>. This much information about Orbit 2 is also encapsulated by the (first order) extended proposition, (uv)((du, v))(dv, u), which says that u and v are not both true at the same time, while du is equal in value to v, and dv is the opposite of u.
Note 21
By way of providing a simple illustration of Cook's Theorem, namely, that "Propositional Satisfiability is NP-Complete", I will describe one way to translate finite approximations of turing machines into propositional expressions, using the cactus language syntax for propositional calculus that I will describe in more detail as we proceed. Notation: Stilt(k) = space and time limited turing machine, with k units of space and k units of time. Stunt(k) = space and time limited turing machine, for computing the parity of a bit string, with number of tape cells of input equal to k. I will follow the pattern of discussion in the book by Herbert Wilf, 'Algorithms and Complexity' (1986), pp. 188-201, but translate his logical formalism into cactus language, which is more efficient in regard to the number of propositional clauses that are required. A turing machine for computing the parity of a bit string is described by means of the following Figure and Table. o-------------------------------------------------o | | | 1/1/+1 | | --------> | | /\ / \ /\ | | 0/0/+1 ^ 0 1 ^ 0/0/+1 | | \/|\ /|\/ | | | <-------- | | | #/#/-1 | 1/1/+1 | #/#/-1 | | | | | | v v | | # * | | | o-------------------------------------------------o Figure 21-a. Parity Machine Table 21-b. Parity Machine o-------o--------o-------------o---------o------------o | State | Symbol | Next Symbol | Ratchet | Next State | | Q | S | S' | dR | Q' | o-------o--------o-------------o---------o------------o | 0 | 0 | 0 | +1 | 0 | | 0 | 1 | 1 | +1 | 1 | | 0 | # | # | -1 | # | | 1 | 0 | 0 | +1 | 1 | | 1 | 1 | 1 | +1 | 0 | | 1 | # | # | -1 | * | o-------o--------o-------------o---------o------------o The TM has a "finite automaton" (FA) as one component. Let us refer to this particular FA by the name of "M". The "tape-head" (that is, the "read-unit") will be called "H". The "registers" are also called "tape-cells" or "tape-squares".
Note 22
To see how each finite approximation to a given turing machine can be given a purely propositional description, one fixes the parameter k and limits the rest of the discussion to describing Stilt(k), which is not really a full-fledged TM anymore but just a finite automaton in disguise. In this example, for the sake of a minimal illustration, we choose k = 2, and discuss Stunt(2). Since the zeroth tape cell and the last tape cell are occupied with the bof and eof marks "#", this amounts to only one digit of significant computation. To translate Stunt(2) into propositional form we use the following collection of basic propositions, boolean variables, or logical features, depending on what one prefers to call them: The basic propositions for describing the "present state function" QF : P -> Q are these: p0_q#, p0_q*, p0_q0, p0_q1, p1_q#, p1_q*, p1_q0, p1_q1, p2_q#, p2_q*, p2_q0, p2_q1, p3_q#, p3_q*, p3_q0, p3_q1. The proposition of the form pi_qj says: At the point-in-time p_i, the finite machine M is in the state q_j. The basic propositions for describing the "present register function" RF : P -> R are these: p0_r0, p0_r1, p0_r2, p0_r3, p1_r0, p1_r1, p1_r2, p1_r3, p2_r0, p2_r1, p2_r2, p2_r3, p3_r0, p3_r1, p3_r2, p3_r3. The proposition of the form pi_rj says: At the point-in-time p_i, the tape-head H is on the tape-cell r_j. The basic propositions for describing the "present symbol function" SF : P -> (R -> S) are these: p0_r0_s#, p0_r0_s*, p0_r0_s0, p0_r0_s1, p0_r1_s#, p0_r1_s*, p0_r1_s0, p0_r1_s1, p0_r2_s#, p0_r2_s*, p0_r2_s0, p0_r2_s1, p0_r3_s#, p0_r3_s*, p0_r3_s0, p0_r3_s1, p1_r0_s#, p1_r0_s*, p1_r0_s0, p1_r0_s1, p1_r1_s#, p1_r1_s*, p1_r1_s0, p1_r1_s1, p1_r2_s#, p1_r2_s*, p1_r2_s0, p1_r2_s1, p1_r3_s#, p1_r3_s*, p1_r3_s0, p1_r3_s1, p2_r0_s#, p2_r0_s*, p2_r0_s0, p2_r0_s1, p2_r1_s#, p2_r1_s*, p2_r1_s0, p2_r1_s1, p2_r2_s#, p2_r2_s*, p2_r2_s0, p2_r2_s1, p2_r3_s#, p2_r3_s*, p2_r3_s0, p2_r3_s1, p3_r0_s#, p3_r0_s*, p3_r0_s0, p3_r0_s1, p3_r1_s#, p3_r1_s*, p3_r1_s0, p3_r1_s1, p3_r2_s#, p3_r2_s*, p3_r2_s0, p3_r2_s1, p3_r3_s#, p3_r3_s*, p3_r3_s0, p3_r3_s1. The proposition of the form pi_rj_sk says: At the point-in-time p_i, the tape-cell r_j bears the mark s_k.
Note 23
Given but a single free square on the tape, there are just two different sets of initial conditions for Stunt(2), the finite approximation to the parity turing machine that we are presently considering. Initial Conditions for Tape Input "0" The following conjunction of 5 basic propositions describes the initial conditions when Stunt(2) is started with an input of "0" in its free square: p0_q0 p0_r1 p0_r0_s# p0_r1_s0 p0_r2_s# This conjunction of basic propositions may be read as follows: At time p_0, M is in the state q_0, and At time p_0, H is reading cell r_1, and At time p_0, cell r_0 contains "#", and At time p_0, cell r_1 contains "0", and At time p_0, cell r_2 contains "#". Initial Conditions for Tape Input "1" The following conjunction of 5 basic propositions describes the initial conditions when Stunt(2) is started with an input of "1" in its free square: p0_q0 p0_r1 p0_r0_s# p0_r1_s1 p0_r2_s# This conjunction of basic propositions may be read as follows: At time p_0, M is in the state q_0, and At time p_0, H is reading cell r_1, and At time p_0, cell r_0 contains "#", and At time p_0, cell r_1 contains "1", and At time p_0, cell r_2 contains "#".
Note 24
A complete description of Stunt(2) in propositional form is obtained by conjoining one of the above choices for initial conditions with all of the following sets of propositions, that serve in effect as a simple type of "declarative program", telling us all that we need to know about the anatomy and behavior of the truncated TM in question. Mediate Conditions: ( p0_q# ( p1_q# )) ( p0_q* ( p1_q* )) ( p1_q# ( p2_q# )) ( p1_q* ( p2_q* )) Terminal Conditions: (( p2_q# )( p2_q* )) State Partition: (( p0_q0 ),( p0_q1 ),( p0_q# ),( p0_q* )) (( p1_q0 ),( p1_q1 ),( p1_q# ),( p1_q* )) (( p2_q0 ),( p2_q1 ),( p2_q# ),( p2_q* )) Register Partition: (( p0_r0 ),( p0_r1 ),( p0_r2 )) (( p1_r0 ),( p1_r1 ),( p1_r2 )) (( p2_r0 ),( p2_r1 ),( p2_r2 )) Symbol Partition: (( p0_r0_s0 ),( p0_r0_s1 ),( p0_r0_s# )) (( p0_r1_s0 ),( p0_r1_s1 ),( p0_r1_s# )) (( p0_r2_s0 ),( p0_r2_s1 ),( p0_r2_s# )) (( p1_r0_s0 ),( p1_r0_s1 ),( p1_r0_s# )) (( p1_r1_s0 ),( p1_r1_s1 ),( p1_r1_s# )) (( p1_r2_s0 ),( p1_r2_s1 ),( p1_r2_s# )) (( p2_r0_s0 ),( p2_r0_s1 ),( p2_r0_s# )) (( p2_r1_s0 ),( p2_r1_s1 ),( p2_r1_s# )) (( p2_r2_s0 ),( p2_r2_s1 ),( p2_r2_s# )) Interaction Conditions: (( p0_r0 ) p0_r0_s0 ( p1_r0_s0 )) (( p0_r0 ) p0_r0_s1 ( p1_r0_s1 )) (( p0_r0 ) p0_r0_s# ( p1_r0_s# )) (( p0_r1 ) p0_r1_s0 ( p1_r1_s0 )) (( p0_r1 ) p0_r1_s1 ( p1_r1_s1 )) (( p0_r1 ) p0_r1_s# ( p1_r1_s# )) (( p0_r2 ) p0_r2_s0 ( p1_r2_s0 )) (( p0_r2 ) p0_r2_s1 ( p1_r2_s1 )) (( p0_r2 ) p0_r2_s# ( p1_r2_s# )) (( p1_r0 ) p1_r0_s0 ( p2_r0_s0 )) (( p1_r0 ) p1_r0_s1 ( p2_r0_s1 )) (( p1_r0 ) p1_r0_s# ( p2_r0_s# )) (( p1_r1 ) p1_r1_s0 ( p2_r1_s0 )) (( p1_r1 ) p1_r1_s1 ( p2_r1_s1 )) (( p1_r1 ) p1_r1_s# ( p2_r1_s# )) (( p1_r2 ) p1_r2_s0 ( p2_r2_s0 )) (( p1_r2 ) p1_r2_s1 ( p2_r2_s1 )) (( p1_r2 ) p1_r2_s# ( p2_r2_s# )) Transition Relations: ( p0_q0 p0_r1 p0_r1_s0 ( p1_q0 p1_r2 p1_r1_s0 )) ( p0_q0 p0_r1 p0_r1_s1 ( p1_q1 p1_r2 p1_r1_s1 )) ( p0_q0 p0_r1 p0_r1_s# ( p1_q# p1_r0 p1_r1_s# )) ( p0_q0 p0_r2 p0_r2_s# ( p1_q# p1_r1 p1_r2_s# )) ( p0_q1 p0_r1 p0_r1_s0 ( p1_q1 p1_r2 p1_r1_s0 )) ( p0_q1 p0_r1 p0_r1_s1 ( p1_q0 p1_r2 p1_r1_s1 )) ( p0_q1 p0_r1 p0_r1_s# ( p1_q* p1_r0 p1_r1_s# )) ( p0_q1 p0_r2 p0_r2_s# ( p1_q* p1_r1 p1_r2_s# )) ( p1_q0 p1_r1 p1_r1_s0 ( p2_q0 p2_r2 p2_r1_s0 )) ( p1_q0 p1_r1 p1_r1_s1 ( p2_q1 p2_r2 p2_r1_s1 )) ( p1_q0 p1_r1 p1_r1_s# ( p2_q# p2_r0 p2_r1_s# )) ( p1_q0 p1_r2 p1_r2_s# ( p2_q# p2_r1 p2_r2_s# )) ( p1_q1 p1_r1 p1_r1_s0 ( p2_q1 p2_r2 p2_r1_s0 )) ( p1_q1 p1_r1 p1_r1_s1 ( p2_q0 p2_r2 p2_r1_s1 )) ( p1_q1 p1_r1 p1_r1_s# ( p2_q* p2_r0 p2_r1_s# )) ( p1_q1 p1_r2 p1_r2_s# ( p2_q* p2_r1 p2_r2_s# ))
Note 25
Interpretation of the Propositional Program Let us now run through the propositional specification of Stunt(2), our truncated TM, and paraphrase what it says in ordinary language. Mediate Conditions: ( p0_q# ( p1_q# )) ( p0_q* ( p1_q* )) ( p1_q# ( p2_q# )) ( p1_q* ( p2_q* )) In the interpretation of the cactus language for propositional logic that we are using here, an expression of the form "(p (q))" expresses a conditional, an implication, or an if-then proposition, commonly read as: "not p without q", "if p then q", "p implies q", "p => q", and so on. A text string expression of the form "(p (q))" corresponds to a graph-theoretic data-structure of the following form: o---------------------------------------o | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` p ` q ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` o---o ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` | ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` @ ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | o---------------------------------------o | ` ` ` ` ` ` ` ( p ( q ))` ` ` ` ` ` ` | o---------------------------------------o Taken together, the Mediate Conditions state the following: If M at p_0 is in state q_#, then M at p_1 is in state q_#, and If M at p_0 is in state q_*, then M at p_1 is in state q_*, and If M at p_1 is in state q_#, then M at p_2 is in state q_#, and If M at p_1 is in state q_*, then M at p_2 is in state q_*.
Note 26
Interpretation of the Propositional Program (cont.) Terminal Conditions: (( p2_q# )( p2_q* )) In cactus syntax, an expression of the form "((p)(q))" expresses the disjunction "p or q". The corresponding cactus graph, here just a tree, has the following shape: o---------------------------------------o | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` p ` q ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` o ` o ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` `\`/` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` o ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` | ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` @ ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | o---------------------------------------o | ` ` ` ` ` ` ` ((p) (q)) ` ` ` ` ` ` ` | o---------------------------------------o In effect, the Terminal Conditions state the following: At time p_2, M is in state q_#, or At time p_2, M is in state q_*.
Note 27
Interpretation of the Propositional Program (cont.)
State Partition:
(( p0_q0 ),( p0_q1 ),( p0_q# ),( p0_q* ))
(( p1_q0 ),( p1_q1 ),( p1_q# ),( p1_q* ))
(( p2_q0 ),( p2_q1 ),( p2_q# ),( p2_q* ))
In cactus syntax, an expression of the form "((e_1),(e_2),(...),(e_k))"
expresses the fact that "exactly one of the e_j is true, for j = 1 to k".
Expressions of this form are called "universal partition" expressions, and
the corresponding "painted and rooted cactus" (PARC) has the following shape:
o---------------------------------------o
| ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` |
| ` ` ` ` e_1 ` e_2 ` ... ` e_k ` ` ` ` |
| ` ` ` ` `o` ` `o` ` ` ` ` `o` ` ` ` ` |
| ` ` ` ` `|` ` `|` ` ` ` ` `|` ` ` ` ` |
| ` ` ` ` `o-----o--- ... ---o` ` ` ` ` |
| ` ` ` ` ` \ ` ` ` ` ` ` ` / ` ` ` ` ` |
| ` ` ` ` ` `\` ` ` ` ` ` `/` ` ` ` ` ` |
| ` ` ` ` ` ` \ ` ` ` ` ` / ` ` ` ` ` ` |
| ` ` ` ` ` ` `\` ` ` ` `/` ` ` ` ` ` ` |
| ` ` ` ` ` ` ` \ ` ` ` / ` ` ` ` ` ` ` |
| ` ` ` ` ` ` ` `\` ` `/` ` ` ` ` ` ` ` |
| ` ` ` ` ` ` ` ` \ ` / ` ` ` ` ` ` ` ` |
| ` ` ` ` ` ` ` ` `\`/` ` ` ` ` ` ` ` ` |
| ` ` ` ` ` ` ` ` ` @ ` ` ` ` ` ` ` ` ` |
| ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` |
o---------------------------------------o
| ` ` ` ((e_1),(e_2),(...),(e_k)) ` ` ` |
o---------------------------------------o
The State Partition segment of the propositional program
consists of three universal partition expressions, taken
in conjunction expressing the condition that M has to be
in one and only one of its states at each point in time
under consideration. In short, we have the constraint:
At each of the points in time p_i, for i in the set {0, 1, 2}
M can be in exactly one state q_j, for j in the set {0, 1, #, *}.
Note 28
Interpretation of the Propositional Program (cont.) Register Partition: (( p0_r0 ),( p0_r1 ),( p0_r2 )) (( p1_r0 ),( p1_r1 ),( p1_r2 )) (( p2_r0 ),( p2_r1 ),( p2_r2 )) The Register Partition segment of the propositional program consists of three universal partition expressions, taken in conjunction saying that the read head H must be reading one and only one of the registers or tape cells available to it at each of the points in time under consideration. In sum: At each of the points in time p_i, for i = 0, 1, 2, H is reading exactly one cell r_j, for j = 0, 1, 2.
Note 29
Interpretation of the Propositional Program (cont.)
Symbol Partition:
(( p0_r0_s0 ),( p0_r0_s1 ),( p0_r0_s# ))
(( p0_r1_s0 ),( p0_r1_s1 ),( p0_r1_s# ))
(( p0_r2_s0 ),( p0_r2_s1 ),( p0_r2_s# ))
(( p1_r0_s0 ),( p1_r0_s1 ),( p1_r0_s# ))
(( p1_r1_s0 ),( p1_r1_s1 ),( p1_r1_s# ))
(( p1_r2_s0 ),( p1_r2_s1 ),( p1_r2_s# ))
(( p2_r0_s0 ),( p2_r0_s1 ),( p2_r0_s# ))
(( p2_r1_s0 ),( p2_r1_s1 ),( p2_r1_s# ))
(( p2_r2_s0 ),( p2_r2_s1 ),( p2_r2_s# ))
The Symbol Partition segment of the propositional program for Stunt(2)
consists of nine universal partition expressions, taken in conjunction
stipulating that there has to be one and only one symbol in each of the
registers at each point in time under consideration. In short, we have:
At each of the points in time p_i, for i in {0, 1, 2},
in each of the tape registers r_j, for j in {0, 1, 2},
there can be exactly one sign s_k, for k in {0, 1, #}.
Note 30
Interpretation of the Propositional Program (cont.) Interaction Conditions: (( p0_r0 ) p0_r0_s0 ( p1_r0_s0 )) (( p0_r0 ) p0_r0_s1 ( p1_r0_s1 )) (( p0_r0 ) p0_r0_s# ( p1_r0_s# )) (( p0_r1 ) p0_r1_s0 ( p1_r1_s0 )) (( p0_r1 ) p0_r1_s1 ( p1_r1_s1 )) (( p0_r1 ) p0_r1_s# ( p1_r1_s# )) (( p0_r2 ) p0_r2_s0 ( p1_r2_s0 )) (( p0_r2 ) p0_r2_s1 ( p1_r2_s1 )) (( p0_r2 ) p0_r2_s# ( p1_r2_s# )) (( p1_r0 ) p1_r0_s0 ( p2_r0_s0 )) (( p1_r0 ) p1_r0_s1 ( p2_r0_s1 )) (( p1_r0 ) p1_r0_s# ( p2_r0_s# )) (( p1_r1 ) p1_r1_s0 ( p2_r1_s0 )) (( p1_r1 ) p1_r1_s1 ( p2_r1_s1 )) (( p1_r1 ) p1_r1_s# ( p2_r1_s# )) (( p1_r2 ) p1_r2_s0 ( p2_r2_s0 )) (( p1_r2 ) p1_r2_s1 ( p2_r2_s1 )) (( p1_r2 ) p1_r2_s# ( p2_r2_s# )) In briefest terms, the Interaction Conditions merely express the circumstance that the mark on a tape cell cannot change between two points in time unless the tape head is over the cell in question at the initial one of those points in time. All that we have to do is to see how they manage to say this. Consider a cactus expression of the following form: (( p<i>_r<j> ) p<i>_r<j>_s<k> ( p<i+1>_r<j>_s<k> )) This expression has the corresponding cactus graph: o---------------------------------------o | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` p<i>_r<j> ` p<i+1>_r<j>_s<k>` | | ` ` ` ` ` ` ` ` o ` o ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` `\`/` ` ` ` ` ` ` ` ` | | ` `p<i>_r<j>_s<k> o ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` | ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` @ ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | o---------------------------------------o A propositional expression of this form can be read as follows: IF: At the time p<i>, the tape cell r<j> bears the mark s<k>, BUT it is NOT the case that: At the time p<i>, the tape head is on the tape cell r<j>, THEN: At the time p<i+1>, the tape cell r<j> bears the mark s<k>. The eighteen clauses of the Interaction Conditions simply impose one such constraint on symbol changes for each combination of the times p_0, p_1, registers r_0, r_1, r_2, and symbols s_0, s_1, s_#.
Note 31
Interpretation of the Propositional Program (cont.) Transition Relations: ( p0_q0 p0_r1 p0_r1_s0 ( p1_q0 p1_r2 p1_r1_s0 )) ( p0_q0 p0_r1 p0_r1_s1 ( p1_q1 p1_r2 p1_r1_s1 )) ( p0_q0 p0_r1 p0_r1_s# ( p1_q# p1_r0 p1_r1_s# )) ( p0_q0 p0_r2 p0_r2_s# ( p1_q# p1_r1 p1_r2_s# )) ( p0_q1 p0_r1 p0_r1_s0 ( p1_q1 p1_r2 p1_r1_s0 )) ( p0_q1 p0_r1 p0_r1_s1 ( p1_q0 p1_r2 p1_r1_s1 )) ( p0_q1 p0_r1 p0_r1_s# ( p1_q* p1_r0 p1_r1_s# )) ( p0_q1 p0_r2 p0_r2_s# ( p1_q* p1_r1 p1_r2_s# )) ( p1_q0 p1_r1 p1_r1_s0 ( p2_q0 p2_r2 p2_r1_s0 )) ( p1_q0 p1_r1 p1_r1_s1 ( p2_q1 p2_r2 p2_r1_s1 )) ( p1_q0 p1_r1 p1_r1_s# ( p2_q# p2_r0 p2_r1_s# )) ( p1_q0 p1_r2 p1_r2_s# ( p2_q# p2_r1 p2_r2_s# )) ( p1_q1 p1_r1 p1_r1_s0 ( p2_q1 p2_r2 p2_r1_s0 )) ( p1_q1 p1_r1 p1_r1_s1 ( p2_q0 p2_r2 p2_r1_s1 )) ( p1_q1 p1_r1 p1_r1_s# ( p2_q* p2_r0 p2_r1_s# )) ( p1_q1 p1_r2 p1_r2_s# ( p2_q* p2_r1 p2_r2_s# )) The Transition Relation segment of the propositional program for Stunt(2) consists of sixteen implication statements with complex antecedents and consequents. Taken together, these give propositional expression to the TM Figure and Table that were given at the outset. Just by way of a single example, consider the clause: ( p0_q0 p0_r1 p0_r1_s1 ( p1_q1 p1_r2 p1_r1_s1 )) This complex implication statement can be read to say: IF: At time p_0, M is in the state q_0, and At time p_0, H is reading cell r_1, and At time p_0, cell r_1 contains "1", THEN: At time p_1, M is in the state q_1, and At time p_1, H is reading cell r_2, and At time p_1, cell r_1 contains "1".
Note 32
Interpretation of the Propositional Program (cont.) The propositional program for Stunt(2) uses the following set of (9 + 12 + 36) = 57 basic propositions or boolean variables: p0_r0, p0_r1, p0_r2, p1_r0, p1_r1, p1_r2, p2_r0, p2_r1, p2_r2. p0_q#, p0_q*, p0_q0, p0_q1, p1_q#, p1_q*, p1_q0, p1_q1, p2_q#, p2_q*, p2_q0, p2_q1. p0_r0_s#, p0_r0_s*, p0_r0_s0, p0_r0_s1, p0_r1_s#, p0_r1_s*, p0_r1_s0, p0_r1_s1, p0_r2_s#, p0_r2_s*, p0_r2_s0, p0_r2_s1, p1_r0_s#, p1_r0_s*, p1_r0_s0, p1_r0_s1, p1_r1_s#, p1_r1_s*, p1_r1_s0, p1_r1_s1, p1_r2_s#, p1_r2_s*, p1_r2_s0, p1_r2_s1, p2_r0_s#, p2_r0_s*, p2_r0_s0, p2_r0_s1, p2_r1_s#, p2_r1_s*, p2_r1_s0, p2_r1_s1, p2_r2_s#, p2_r2_s*, p2_r2_s0, p2_r2_s1. This means that the propositional program itself is nothing more or less than a single proposition or a boolean function P : B^57 -> B. An assignment of boolean values to the above set of boolean variables is called an "interpretation" of P, and any interpretation of P that makes the proposition P : B^57 -> B evaluate to 1 is referred to as a "satisfying interpretation" of the proposition P. Another way to specify interpretations, instead of giving them as bit vectors in B^57 and trying to remember some arbitrary ordering of variables, is to give them in the form of "singular propositions", that is, a conjunction of the form "e_1 & ... & e_57" where each e_j is either "v_j" or "(v_j)", that is, either the assertion or the negation of the boolean variable v_j, as j runs from 1 to 57. Even more briefly, the same information can be communicated simply by giving the conjunction of the asserted variables, with the understanding that each of the others is negated. A satisfying interpretation of the proposition P supplies us with all the information of a complete execution history for the corresponding program, and so all we have to do in order to get the output of the program P is to read off the proper part of the data from the expression of this interpretation.
Note 33
Interpretation of the Propositional Program (concl.) One component of the Theme One program that I wrote some years ago finds all the satisfying interpretations of propositions expressed in cactus syntax. It's not a polynomial time algorithm, as you may guess, but it was just barely efficient enough to do this example in the 500 K of spare memory that I had on an old 286 PC in about 1989, so I will give you the actual outputs from those trials. Output Conditions for Tape Input "0" Let P_0 be the proposition that we get by conjoining the proposition that describes the initial conditions for tape input "0" with the proposition that describes the truncated turing machine Stunt(2). As it turns out, P_0 has a single satisfying interpretation, and this is represented as a singular proposition in terms of its positive logical features in the following display: o-------------------------------------------------o | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | p0_q0 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | `p0_r1` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` p0_r0_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` `p0_r1_s0 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` p0_r2_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` `p1_q0` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` p1_r2 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` `p1_r2_s# ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` p1_r0_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` `p1_r1_s0 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` p2_q# ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` `p2_r1` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` p2_r0_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` `p2_r1_s0 ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` p2_r2_s#` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | o-------------------------------------------------o The Output Conditions for Tape Input "0" can be read as follows: At the time p_0, M is in the state q_0, and At the time p_0, H is reading cell r_1, and At the time p_0, cell r_0 contains "#", and At the time p_0, cell r_1 contains "0", and At the time p_0, cell r_2 contains "#", and At the time p_1, M is in the state q_0, and At the time p_1, H is reading cell r_2, and At the time p_1, cell r_0 contains "#", and At the time p_1, cell r_1 contains "0", and At the time p_1, cell r_2 contains "#", and At the time p_2, M is in the state q_#, and At the time p_2, H is reading cell r_1, and At the time p_2, cell r_0 contains "#", and At the time p_2, cell r_1 contains "0", and At the time p_2, cell r_2 contains "#". The output of Stunt(2) being the symbol that rests under the tape head H if and when the machine M reaches one of its resting states, we get the result that Parity(0) = 0. Output Conditions for Tape Input "1" Let P_1 be the proposition that we get by conjoining the proposition that describes the initial conditions for tape input "1" with the proposition that describes the truncated turing machine Stunt(2). As it turns out, P_1 has a single satisfying interpretation, and this is represented as a singular proposition in terms of its positive logical features in the following display: o-------------------------------------------------o | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | p0_q0 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | `p0_r1` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` p0_r0_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` `p0_r1_s1 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` p0_r2_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` `p1_q1` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` p1_r2 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` `p1_r2_s# ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` p1_r0_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` `p1_r1_s1 ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` p2_q* ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` `p2_r1` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` p2_r0_s#` ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` `p2_r1_s1 ` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` p2_r2_s#` ` ` ` ` ` ` ` ` ` ` ` ` | | ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` ` | o-------------------------------------------------o The Output Conditions for Tape Input "1" can be read as follows: At the time p_0, M is in the state q_0, and At the time p_0, H is reading cell r_1, and At the time p_0, cell r_0 contains "#", and At the time p_0, cell r_1 contains "1", and At the time p_0, cell r_2 contains "#", and At the time p_1, M is in the state q_1, and At the time p_1, H is reading cell r_2, and At the time p_1, cell r_0 contains "#", and At the time p_1, cell r_1 contains "1", and At the time p_1, cell r_2 contains "#", and At the time p_2, M is in the state q_*, and At the time p_2, H is reading cell r_1, and At the time p_2, cell r_0 contains "#", and At the time p_2, cell r_1 contains "1", and At the time p_2, cell r_2 contains "#". The output of Stunt(2) being the symbol that rests under the tape head H when and if the machine M reaches one of its resting states, we get the result that Parity(1) = 1.
Work Area
DATA 20. http://forum.wolframscience.com/showthread.php?postid=791#post791 Let's see how this information about the transformation F, arrived at by eyeballing the raw data, comports with what we derived through a more systematic symbolic computation. The results of the various operator actions that we have just computed are summarized in Tables 66-i and 66-ii from my paper, and I have attached these as a text file below. Table 66-i. Computation Summary for f<u, v> = ((u)(v)) o--------------------------------------------------------------------------------o | | | !e!f = uv. 1 + u(v). 1 + (u)v. 1 + (u)(v). 0 | | | | Ef = uv. (du dv) + u(v). (du (dv)) + (u)v.((du) dv) + (u)(v).((du)(dv)) | | | | Df = uv. du dv + u(v). du (dv) + (u)v. (du) dv + (u)(v).((du)(dv)) | | | | df = uv. 0 + u(v). du + (u)v. dv + (u)(v). (du, dv) | | | | rf = uv. du dv + u(v). du dv + (u)v. du dv + (u)(v). du dv | | | o--------------------------------------------------------------------------------o Table 66-ii. Computation Summary for g<u, v> = ((u, v)) o--------------------------------------------------------------------------------o | | | !e!g = uv. 1 + u(v). 0 + (u)v. 0 + (u)(v). 1 | | | | Eg = uv.((du, dv)) + u(v). (du, dv) + (u)v. (du, dv) + (u)(v).((du, dv)) | | | | Dg = uv. (du, dv) + u(v). (du, dv) + (u)v. (du, dv) + (u)(v). (du, dv) | | | | dg = uv. (du, dv) + u(v). (du, dv) + (u)v. (du, dv) + (u)(v). (du, dv) | | | | rg = uv. 0 + u(v). 0 + (u)v. 0 + (u)(v). 0 | | | o--------------------------------------------------------------------------------o o---------------------------------------o | | | o | | / \ | | / \ | | / \ | | o o | | / \ / \ | | / \ / \ | | / \ / \ | | o o o | | / \ / \ / \ | | / \ / \ / \ | | / \ / \ / \ | | o o o o | | / \ / \ / \ / \ | | / \ / \ / \ / \ | | / \ / \ / \ / \ | | o o o o o | | |\ / \ / \ / \ /| | | | \ / \ / \ / \ / | | | | \ / \ / \ / \ / | | | | o o o o | | | | |\ / \ / \ /| | | | | | \ / \ / \ / | | | | | u | \ / \ / \ / | v | | | o---+---o o o---+---o | | | \ / \ / | | | | \ / \ / | | | | du \ / \ / dv | | | o-------o o-------o | | \ / | | \ / | | \ / | | o | | | o---------------------------------------o
Discussion
PD = Philip Dutton
PD: I've been watching your posts.
PD: I am not an expert on logic infrastructures but I find the posts
interesting (despite not understanding much of it). I am like
the diagrams. I have recently been trying to understand CA's
using a particular perspective: sinks and sources. I think
that all CA's are simply combinations of sinks and sources.
How they interact (or intrude into each other's domains)
would most likely be a result of the rules (and initial
configuration of on or off cells).
PD: Anyway, to be short, I "see" diamond shapes quite often in
your diagrams. Triangles (either up or down) or diamonds
(combination of an up and down triangle) make me think
soley of sinks and sources. I think of the diamond to
be a source which, during the course of progression,
is expanding (because it is producing) and then starts
to act as a sink (because it consumes) -- and hence the
diamond. I can't stop thinking about sinks and sources in
CA's and so I thought I would ask you if there is some way
to tie the two worlds together (CA's of sinks and sources
together with your differential constructs).
PD: Any thoughts?
Yes, I'm hoping that there's a lot of stuff analogous to
R-world dynamics to be discovered in this B-world variety,
indeed, that's kind of why I set out on this investigation --
oh, gee, has it been that long? -- I guess about 1989 or so,
when I started to see this "differential logic" angle on what
I had previously studied in systems theory as the "qualitative
approach to differential equations". I think we used to use the
words "attractor" and "basin" more often than "sink", but a source
is still a source as time goes by, and I do remember using the word
"sink" a lot when I was a freshperson in physics, before I got logic.
I have spent the last 15 years doing a funny mix of practice in stats
and theory in math, but I did read early works by Von Neumann, Burks,
Ulam, and later stuff by Holland on CA's. Still, it may be a while
before I have re-heated my concrete intuitions about them in the
NKS way of thinking.
There are some fractal-looking pictures that emerge when
I turn to "higher order propositional expressions" (HOPE's).
I have discussed this topic elswhere on the web and can look
it up now if your are interested, but I am trying to make my
e-positions somewhat clearer for the NKS forum than I have
tried to do before.
But do not hestitate to dialogue all this stuff on the boards,
as that's what always seems to work the best. What I've found
works best for me, as I can hardly remember what I was writing
last month without Google, is to archive a copy at one of the
other Google-visible discussion lists that I'm on at present.
Document History
DATA. Differential Analytic Turing Automata Ontology List 01. http://suo.ieee.org/ontology/msg05457.html 02. http://suo.ieee.org/ontology/msg05458.html 03. http://suo.ieee.org/ontology/msg05459.html 04. http://suo.ieee.org/ontology/msg05460.html 05. http://suo.ieee.org/ontology/msg05461.html 06. http://suo.ieee.org/ontology/msg05462.html 07. http://suo.ieee.org/ontology/msg05463.html 08. http://suo.ieee.org/ontology/msg05464.html 09. http://suo.ieee.org/ontology/msg05465.html 10. http://suo.ieee.org/ontology/msg05466.html 11. http://suo.ieee.org/ontology/msg05467.html 12. http://suo.ieee.org/ontology/msg05469.html 13. http://suo.ieee.org/ontology/msg05470.html 14. http://suo.ieee.org/ontology/msg05471.html 15. http://suo.ieee.org/ontology/msg05472.html 16. http://suo.ieee.org/ontology/msg05473.html 17. http://suo.ieee.org/ontology/msg05474.html 18. http://suo.ieee.org/ontology/msg05475.html 19. http://suo.ieee.org/ontology/msg05476.html 20. http://suo.ieee.org/ontology/msg05479.html Inquiry List 00. http://stderr.org/pipermail/inquiry/2004-February/thread.html#1228 00. http://stderr.org/pipermail/inquiry/2004-March/thread.html#1235 00. http://stderr.org/pipermail/inquiry/2004-March/thread.html#1240 00. http://stderr.org/pipermail/inquiry/2004-June/thread.html#1630 01. http://stderr.org/pipermail/inquiry/2004-February/001228.html 02. http://stderr.org/pipermail/inquiry/2004-February/001230.html 03. http://stderr.org/pipermail/inquiry/2004-February/001231.html 04. http://stderr.org/pipermail/inquiry/2004-February/001232.html 05. http://stderr.org/pipermail/inquiry/2004-February/001233.html 06. http://stderr.org/pipermail/inquiry/2004-February/001234.html 07. http://stderr.org/pipermail/inquiry/2004-March/001235.html 08. http://stderr.org/pipermail/inquiry/2004-March/001236.html 09. http://stderr.org/pipermail/inquiry/2004-March/001237.html 10. http://stderr.org/pipermail/inquiry/2004-March/001238.html 11. http://stderr.org/pipermail/inquiry/2004-March/001240.html 12. http://stderr.org/pipermail/inquiry/2004-March/001242.html 13. http://stderr.org/pipermail/inquiry/2004-March/001243.html 14. http://stderr.org/pipermail/inquiry/2004-March/001244.html 15. http://stderr.org/pipermail/inquiry/2004-March/001245.html 16. http://stderr.org/pipermail/inquiry/2004-March/001246.html 17. http://stderr.org/pipermail/inquiry/2004-March/001247.html 18. http://stderr.org/pipermail/inquiry/2004-March/001248.html 19. http://stderr.org/pipermail/inquiry/2004-March/001249.html 20. http://stderr.org/pipermail/inquiry/2004-March/001255.html 21. http://stderr.org/pipermail/inquiry/2004-June/001630.html 22. http://stderr.org/pipermail/inquiry/2004-June/001631.html 23. http://stderr.org/pipermail/inquiry/2004-June/001632.html 24. http://stderr.org/pipermail/inquiry/2004-June/001633.html 25. http://stderr.org/pipermail/inquiry/2004-June/001634.html 26. http://stderr.org/pipermail/inquiry/2004-June/001635.html 27. http://stderr.org/pipermail/inquiry/2004-June/001636.html 28. http://stderr.org/pipermail/inquiry/2004-June/001637.html 29. http://stderr.org/pipermail/inquiry/2004-June/001638.html 30. http://stderr.org/pipermail/inquiry/2004-June/001639.html 31. http://stderr.org/pipermail/inquiry/2004-June/001640.html 32. http://stderr.org/pipermail/inquiry/2004-June/001641.html 33. http://stderr.org/pipermail/inquiry/2004-June/001642.html NKS Forum 00. http://forum.wolframscience.com/showthread.php?threadid=228 01. http://forum.wolframscience.com/showthread.php?postid=664#post664 02. http://forum.wolframscience.com/showthread.php?postid=666#post666 03. http://forum.wolframscience.com/showthread.php?postid=677#post677 04. http://forum.wolframscience.com/showthread.php?postid=684#post684 05. http://forum.wolframscience.com/showthread.php?postid=689#post689 06. http://forum.wolframscience.com/showthread.php?postid=697#post697 07. http://forum.wolframscience.com/showthread.php?postid=708#post708 08. http://forum.wolframscience.com/showthread.php?postid=721#post721 09. http://forum.wolframscience.com/showthread.php?postid=722#post722 10. http://forum.wolframscience.com/showthread.php?postid=725#post725 11. http://forum.wolframscience.com/showthread.php?postid=733#post733 12. http://forum.wolframscience.com/showthread.php?postid=756#post756 13. http://forum.wolframscience.com/showthread.php?postid=759#post759 14. http://forum.wolframscience.com/showthread.php?postid=764#post764 15. http://forum.wolframscience.com/showthread.php?postid=766#post766 16. http://forum.wolframscience.com/showthread.php?postid=767#post767 17. http://forum.wolframscience.com/showthread.php?postid=773#post773 18. http://forum.wolframscience.com/showthread.php?postid=775#post775 19. http://forum.wolframscience.com/showthread.php?postid=777#post777 20. http://forum.wolframscience.com/showthread.php?postid=791#post791 21. http://forum.wolframscience.com/showthread.php?postid=1458#post1458 22. http://forum.wolframscience.com/showthread.php?postid=1461#post1461 23. http://forum.wolframscience.com/showthread.php?postid=1463#post1463 24. http://forum.wolframscience.com/showthread.php?postid=1464#post1464 25. http://forum.wolframscience.com/showthread.php?postid=1467#post1467 26. http://forum.wolframscience.com/showthread.php?postid=1469#post1469 27. http://forum.wolframscience.com/showthread.php?postid=1470#post1470 28. http://forum.wolframscience.com/showthread.php?postid=1471#post1471 29. http://forum.wolframscience.com/showthread.php?postid=1473#post1473 30. http://forum.wolframscience.com/showthread.php?postid=1475#post1475 31. http://forum.wolframscience.com/showthread.php?postid=1479#post1479 32. http://forum.wolframscience.com/showthread.php?postid=1489#post1489 33. http://forum.wolframscience.com/showthread.php?postid=1490#post1490
